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How to derive
Link | by Kermit on 2009-09-21 23:04:13
Can some one help me derive "hydrostatic pressure" by using the first laws ? (e.g. F=ma)
prof was really helpful in explaining ... and its going to be on the mid-term for sure so can anyone help ?

Please and thanks yous ^^

Re: How to derive
Link | by Hansbach on 2009-10-31 11:42:16
If you are talking about the derivation of the P=ρgh P= pressure of water at acertain depth. Then first take F=ma (1) p=F/A (2) ρ=m/V (3)

Take eq.1 and substitute it in eq.2 it should become "p=ma/A" where a=acceleration and A=Area
Take eq.3 and rearrange it as m=ρV then substitute in "p=ma/A" this ahould give eq.4 "p=ρVa/A" Now if you realize that Volume or V=A x H i.e volume is equal to Area muliplied by height,all that remains is to substitute This equation into the formula and "p=ρ(A x H)a/A". A and A cancel each other and here you have it. replace a with g as the acceleration acting at all times will be equal to g, and you have the formula P=ρgh

ρ= density
p=simple pressure formula
F=Force

Pretend that I am saying somethiong profound.......

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